1852 United States presidential election in New Jersey

1852 United States presidential election in New Jersey

← 1848 November 2, 1852 1856 →

Nominee Franklin Pierce Winfield Scott Party Democratic Whig Home state New Hampshire New Jersey Running mate William R. King William A. Graham Electoral vote 7 0 Popular vote 44,305 38,556 Percentage 53.24% 44.97%

County Results Pierce   40-50%   50-60%   60-70%   70-80% Scott   40-50%   50-60%   60-70%

President before election Millard Fillmore Whig Elected President Franklin Pierce Democratic

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v t e

The 1852 United States presidential election in New Jersey took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

New Jersey voted for the Democratic candidate, Franklin Pierce, over the Whig Party candidate, Winfield Scott. Pierce won the state by a margin of 6.91%, making him the first Democratic presidential candidate since Andrew Jackson in 1832 to win the state. This is the last time that a Democrat won without carrying Middlesex County.

1852 United States presidential election in New Jersey[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Franklin Pierce of New Hampshire	William Rufus DeVane King of Alabama	44,305	53.24%	7	100.00%
	Whig	Winfield Scott of New Jersey	William Alexander Graham of North Carolina	38,556	46.33%	0	0.00%
	Free Soil	John Parker Hale of New Hampshire	George Washington Julian of Indiana	359	0.43%	0	0.00%
Total				83,220	100.00%	7	100.00%

• United States presidential elections in New Jersey