1966 United States Senate election in Rhode Island

1966 United States Senate election in Rhode Island

← 1960 November 8, 1966 1972 →

Nominee Claiborne Pell Ruth M. Briggs Party Democratic Republican Popular vote 219,331 104,838 Percentage 67.66% 32.34%

County results Municipality results Pell:      50–60%      60–70%      70–80%      80–90% Briggs:      50–60%

U.S. senator before election Claiborne Pell Democratic Elected U.S. Senator Claiborne Pell Democratic

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v t e

The 1966 United States Senate election in Rhode Island took place on November 8, 1966. Incumbent Democratic U.S. Senator Claiborne Pell successfully sought re-election, defeating Republican Ruth M. Briggs with 67.66% of the vote.

Primary elections were held on September 13, 1966.

• Claiborne Pell, incumbent U.S. Senator

Democratic primary results^[1][2]

Party		Candidate	Votes	%
	Democratic	Claiborne Pell (Incumbent)		unopposed

• Ruth M. Briggs, former lieutenant colonel in the Women's Army Corps (WAC)^[3]
• Charles H. Eden

Republican primary results^[1][2]

Party		Candidate	Votes	%
	Republican	Ruth M. Briggs	15,451	82.13%
	Republican	Charles H. Eden	3,363	17.87%
Total votes			18,814	100.00%

General election results ^[4][5][6][7]

Party		Candidate	Votes	%
	Democratic	Claiborne Pell (Incumbent)	219,331	67.66
	Republican	Ruth M. Briggs	104,838	32.34
Majority			114,493	35.32
Turnout			324,169
	Democratic hold

• Congressional Elections, 1946-1996. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-248-4.
• Scammon, Richard M., ed. (1968). America Votes 7: a handbook of contemporary American election statistics, 1966. Washington, D.C.: Governmental Affairs Institute.